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Unity Gain Buffer Initial Conditions

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schematic

simulate this circuit – Schematic created using CircuitLab

A typical way of analysing the unity gain buffer is:

Where A is Open Loop Gain

Vout = A(Vin - Vp) and Vp = Vout therefore

Vout = A(Vin - Vout)

Vout = AVin - AVout

Vout + AVout = AVin

Vout (1+A) = AVin

Vout / Vin = A / (1+A)

if A >> then 1+A ~ A

Vout / Vin = A/A = 1

I would like to get an understanding of how this works from initial conditions ie step response

At t= -1 Vin, Vp and Vout = 0

At t= 0 Vin = 1V and as Vp = 0, Vout = A(1-0) = A

As Vout = A then Vp = A such that Vout = A(1 - A) = A - A^2

Subbing again gives Vout = A(1 - (A-A^2) = A(1-A+A^2)

This is obviously just going to run away so must be incorrect, perhaps it is my initial condition assumption that is wrong?

Alternatively using the simplified model of an op amp:

Op Amp Simplified Model

I could assume that at t=0 Vp = Vin therefore Vout = Vin

However Vin = A(Vin - Vin) is a contradiction

Obviously this is a well known circuit so I must have a fundamental misunderstanding but what have I got wrong?

*Edit

Just to clarify the purpose in asking,

I'm trying to get an understanding of how negative feedback works. The standard analysis at the start of the question is effectively time independent and I would like to know how the output rises with time


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